physics / Classical Mechanics / free

Lagrangian Mechanics

Find motion by following energy through a system.

Follow the mechanism1 / 3

Endpoints are fixed. Every candidate path starts and ends at the same positions and times; only the route between them varies.

the true path makes the action stationaryS = ∫(T − V) dt
q(t): true path (dark) vs varied path, same endpointst = 2action S(ε)minimum at ε = 0

Simplified: a unit mass on a unit spring (m = k = 1), so T = ½q̇² and V = ½q². Every candidate starts at q = 0 and ends at q = sin 2 when t = 2; varied paths add ε·sin(πt/2). Over this short time the true path is a minimum of S; over longer times it can be a saddle, which is why the principle says “stationary”.

action S-0.006
ΔS vs true path0.183
T + V drift0.598

This varied path keeps both endpoints but raises the action by 0.183 ≈ 0.734·ε². First-order changes cancel; that is what “stationary” means. Its T + V also drifts by 0.598, so Newton's laws would not allow it.

04 / PRACTICE

Make the idea yours.

0 / 3 checked

Use the model, then answer without looking back. Each check isolates one decision a learner should be able to make after this lesson.

CHECK 1 / 3

What does the Euler–Lagrange equation determine?